Calculate torque from applied force and moment arm (T = F × r) with SI and Imperial unit support.
Example Result
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The same M10 class 8.8 bolt has two correct torque values: about 50 N·m with dry threads (K ≈ 0.20) and about 37 N·m with oiled threads (K ≈ 0.15). T = K × F × d: oil cuts thread friction, so tightening an oiled bolt to the dry value raises the clamp load from about 25 kN to about 34 kN, right at proof load.
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Torque is the rotational equivalent of linear force — it measures how much a force causes an object to rotate about a pivot or axis. The torque formula T = F × r states that torque equals the applied force multiplied by the perpendicular distance from the pivot point to where the force is applied, a distance known as the moment arm or lever arm. Engineers use torque calculations every day: selecting the right motor for a drive system, specifying torque wrench settings for bolted joints, designing shafts and couplings, and calculating the mechanical advantage of levers and gear trains. This calculator supports both SI units — Newtons and metres producing Newton-metres — and Imperial units — pound-force and feet producing pound-feet. It automatically converts your result across all common torque units so you can compare values or carry the figure into the next stage of your design.
Select your unit system — SI (metric) or Imperial.
Enter the force applied in Newtons (SI) or pound-force (Imperial).
Enter the moment arm — the perpendicular distance from the pivot to where the force acts.
Press Calculate. The result is shown in all common torque units automatically.
By O.E. — Partner, chairman of the board and CEO of a metal products manufacturer for 21 years; the company exports to 45 countries.
Drafted with AI assistance; calculations checked against primary sources and tested with the site's own code. About FlowUtil
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FlowUtil applies the fundamental torque relation T = F × r, where T is the torque, F is the applied force, and r is the perpendicular moment arm from the rotation axis to the line of action of the force. In SI units a force in newtons multiplied by a moment arm in metres gives torque in newton-metres (N·m); in Imperial units a force in pound-force multiplied by a moment arm in feet gives pound-feet (lb·ft). The result is converted across N·m, kN·m, lb·ft, and lb·in so the same figure can be carried into the next design step in whichever unit is needed.
The formula assumes the force is applied perpendicular to the moment arm. If the force acts at an angle θ to the arm, the effective torque is F × r × sin(θ); this calculator covers the common case where the force is applied at 90°, so sin(θ) = 1 and the full product contributes. The conversion factor 1 N·m = 0.737562 lb·ft is exact to the precision shown and derives from the defined relationships between newtons, pounds-force, metres, and feet.
| Symbol | Meaning |
|---|---|
| T | Torque (N·m or lb·ft) |
| F | Applied force, perpendicular to the arm (N or lbf) |
| r | Moment arm — perpendicular distance from axis to force line (m or ft) |
1SI: 500 N applied at a 0.25 m moment arm.
T = F × r = 500 × 0.25 = 125 N·m
T = 125 N·m · ≈ 92.20 lb·ft
A 500 N push on a 0.25 m wrench produces 125 N·m of torque — a typical small servo or hand-tightened industrial joint. The same force on a 0.5 m arm would double the torque to 250 N·m, which is why longer wrenches loosen stubborn bolts more easily.
2SI: 2000 N applied at a 0.05 m motor shaft radius.
T = 2000 × 0.05 = 100 N·m
T = 100 N·m · ≈ 73.76 lb·ft
A belt delivering 2000 N of tangential pull on a 50 mm pitch radius loads the shaft with 100 N·m of torque. Combined with the shaft speed, this figure feeds directly into the Power Calculator (P = T × ω) to size the motor.
3Imperial: 75 lbf applied at a 2 ft moment arm.
T = F × r = 75 × 2 = 150 lb·ft
T = 150 lb·ft · ≈ 203.37 N·m
A 75 lbf pull on a 2-foot breaker bar gives 150 lb·ft — a common wheel-lug or large-bolt tightening range. Note the unit is pound-feet (lb·ft) for torque, distinct from foot-pounds (ft·lbf) used for energy; the numerical value is the same but the physical quantity differs.
The result is a rotational moment expressed in N·m (SI) or lb·ft (Imperial). Physically it represents the tendency of the applied force to rotate the object about the axis; a larger torque means more rotational effect for the same geometry. The four unit stats let you read the same torque in whichever convention a datasheet, standard, or colleague uses.
Torque alone does not determine whether a shaft or bolt will survive — it must be combined with geometry to find stress (torsional shear τ = T·r/J) or with angular speed to find power (P = T × ω). Treat the torque value as an input to those downstream checks rather than as a pass/fail number on its own.
The calculation assumes a perpendicular force and a rigid, frictionless moment arm. Real systems include bearing friction, shaft flexibility, and force components that are not perfectly tangential, all of which reduce the effective torque delivered to the load.
Typical engineering situations where this calculation is needed.
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